Question

The table below shows the ages of children in a particular orphanage home.

Age: 1, 2, 3, 4, 5, 6
No. of children: 10, 15, 21, 20, 16, 18

Use the information to find the: (i) Mean (ii) Median (iii) Mode (iv) Range

Accepted Answer

Total number of children = 10 + 15 + 21 + 20 + 16 + 18 = 100.

(i) Mean: Σfx = (1×10) + (2×15) + (3×21) + (4×20) + (5×16) + (6×18) = 10 + 30 + 63 + 80 + 80 + 108 = 371.
Mean = 371 ÷ 100 = 3.71.

(ii) Median: cumulative frequencies are 10, 25, 46, 66, 82, 100. The 50th and 51st children both fall in age 4, so the median = 4.

(iii) Mode: the highest frequency is 21, which belongs to age 3. Mode = 3.

(iv) Range = 6 − 1 = 5.

BECE Mathematics 2023 Theory — Question 2