JSCE Mathematics 2024 Objective — Question 58

Question 58 of 80 from the Junior Secondary Certificate Examination (JSCE) Mathematics 2024 Objective paper, with the correct answer and a full explanation.

Find the value of X, given that X(three) ÷ 101(three) = 12112(three)

A. X(three) = 200110(three)
B. X(three) = 1210010(three)
C. X(three) = 2001012(three)Correct
D. X(three) = 2010102(three)

Explanation

12112(three) = 149 and 101(three) = 10 in base ten. X = 149 x 10 = 1490, which is 2001012(three).

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