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JSCE Mathematics 2024 Objective — Question 66

Question 66 of 80 from the Junior Secondary Certificate Examination (JSCE) Mathematics 2024 Objective paper, with the correct answer and a full explanation.

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Simplify (4y + 1)/3 - (y - 5)/12 + (4y - 35)/2

  • A. (3y - 3)/5
  • B. (5 + 9y)/12
  • C. 1/4 (5y + 3)
  • D. 1/4 (13y - 67)Correct

Explanation

Common denominator 12: [4(4y + 1) - (y - 5) + 6(4y - 35)] / 12 = (39y - 201) / 12 = (13y - 67) / 4.

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