Question

1. The dimensions of a square is given as one side 6.25cm. A student measured one side of the square as 6.12cm to calculate the perimeter and area. Find the percentage error in the: i. Measured length ii. Calculated perimeter iii. Calculated area

Accepted Answer

i. % error in length = |6.25-6.12|/6.25 x 100% = 2.08%.
ii. True perimeter = 4x6.25 = 25cm. Measured perimeter = 4x6.12 = 24.48cm. % error in perimeter = (25-24.48)/25 x 100% = 2.08%.
iii. True area = 6.25^2 = 39.0625cm^2. Measured area = 6.12^2 = 37.4544cm^2. % error in area = (39.0625-37.4544)/39.0625 x 100% = 4.11%.

NECO Mathematics 2007 Theory — Question 1

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