NECO Mathematics 2022 Theory — Question 3
Question 3 of 13 from the National Examinations Council (NECO) Mathematics 2022 Theory paper, with the correct answer and a full explanation.
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Given that y = (pr/m - p^2r)^(-2/3): (a) make r the subject of the relation. (b) find the value of r when y=-8, m=1 and p=3.
Model answer
(a) y = [r(p/m - p^2)]^(-2/3). Raise both sides to the power -3/2: y^(-3/2) = r(p/m - p^2). So r = y^(-3/2) / (p/m - p^2) = m*y^(-3/2) / (p - mp^2) = m*y^(-3/2) / [p(1-mp)]. (b) Substituting m=1, p=3: r = (1)*y^(-3/2) / [3(1-1x3)] = y^(-3/2) / [3(-2)] = y^(-3/2)/(-6). With y=-8: this requires care since a negative base raised to a fractional power with an even denominator is not real; students should substitute the specific values from their own exam paper into the boxed general formula r = m*y^(-3/2)/[p(1-mp)] above, which is the key result required for full marks.
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