Post-UTME Chemistry 2010 Objective — Question 6
Question 6 of 11 from the Post-UTME Screening (Post-UTME) Chemistry 2010 Objective paper, with the correct answer and a full explanation.
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How many grammes of HCl will be required to react with 10g of NaOH (H=1, Cl=35.5, Na=23, O=16)?
- A. 9.125gCorrect
- B. 4.6g
- C. 10.1g
- D. 18.4g
Explanation
Moles NaOH = 10/40 = 0.25mol. HCl + NaOH -> NaCl + H2O (1:1). Moles HCl = 0.25mol; mass = 0.25 x 36.5 = 9.125g.
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