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Post-UTME Chemistry 2013 Objective — Question 8

Question 8 of 22 from the Post-UTME Screening (Post-UTME) Chemistry 2013 Objective paper, with the correct answer and a full explanation.

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If 100cm3 of oxygen passes through a porous plug in 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is

  • A. 10.0s
  • B. 12.5sCorrect
  • C. 17.7s
  • D. 32.0s

Explanation

By Graham's law, rate is inversely proportional to sqrt(molar mass). t(H2) = t(O2) x sqrt(M(H2)/M(O2)) = 50 x sqrt(2/32) = 50/4 = 12.5s. (No printed answer key for this session; answer worked out independently.)

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