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Post-UTME Chemistry 2015 Objective — Question 11

Question 11 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2015 Objective paper, with the correct answer and a full explanation.

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The equation which illustrates the oxidizing property of Sulphur (IV) oxide is

  • A. 2H2S(g) + SO2(g) -> 3S(s) + 2H2O(l)Correct
  • B. 2NaOH(aq) + SO2(g) -> Na2SO3(aq) + H2O(l)
  • C. 2KMnO4(aq) + SO2(g) + H2O(l) -> K2SO4(aq) + 2MnSO4(aq) + 2H2O(l)
  • D. Fe2(SO4)3(aq) + SO2(g) + 2H2O(l) -> 2FeSO4(aq) + 2H2SO4(aq)

Explanation

In this reaction, SO2 is reduced (S goes from +4 to 0) while oxidising H2S (S from -2 to 0), demonstrating its role as an oxidizing agent.

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