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Post-UTME Chemistry 2015 Objective — Question 6

Question 6 of 20 from the Post-UTME Screening (Post-UTME) Chemistry 2015 Objective paper, with the correct answer and a full explanation.

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CO(g) + 2H2(g) <=> CH3OH(g), delta H = -92 kJ mol-1. From the equation above, calculate the quantity of heat evolved when 6.4g of methanol is produced. [C=12, H=1, O=16]

  • A. 92.0kj
  • B. 46.0kj
  • C. 18.4kjCorrect
  • D. 9.2kj

Explanation

Molar mass CH3OH = 32g/mol. Moles = 6.4/32 = 0.2mol. Heat evolved = 0.2 x 92 = 18.4kJ.

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