Post-UTME English Language 2010 Objective — Question 11
Question 11 of 30 from the Post-UTME Screening (Post-UTME) English Language 2010 Objective paper, with the correct answer and a full explanation.
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A motor-car is uniformly retarded and brought to rest from a speed of 90km/h in 10s. Find its acceleration.
- A. 2.5ms^-2
- B. 2.5ms^-2 (variant)
- C. -2.5ms^-2Correct
- D. -2.5ms^-1
Explanation
90km/h = 25m/s. Deceleration = (0-25)/10 = -2.5ms^-2.
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