Mathematics 2008 Objective — Question 1
If a*b=√(ab), evaluate 2*(12*27)
- A. 12
- B. 9
- C. 6Correct
- D. 2
Explanation
12*27=√(12×27)=√324=18. Then 2*18=√36=6.
All 16 questions from the Post-UTME Screening (Post-UTME) Mathematics 2008 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.
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If a*b=√(ab), evaluate 2*(12*27)
12*27=√(12×27)=√324=18. Then 2*18=√36=6.
Find the sum to infinity of the sequence 1, 9/10, (9/10)², (9/10)³, ...
GP with a=1, r=9/10. Sum = 1/(1-0.9) = 10.
Find the value of k if |-2 1 1; 2 1 k; 1 3 -1| = 23
Expanding the determinant gives 9+7k=23, so k=2.
If X=[[1,2],[0,3]] and Y=[[2,1],[4,3]], find XY
Multiplying: row1=[1×2+2×4, 1×1+2×3]=[10,7]; row2=[0×2+3×4, 0×1+3×3]=[12,9].
In a triangle XYZ, ∠YXZ=44° and ∠XYZ=112°. Calculate the acute angle between the internal bisectors of ∠XYZ and ∠XZY
∠XZY=24°. The angle between the two bisectors is 90+22=112°, so the acute angle is 180-112=68°.
Find the distance between two towns, one at P(45°N,30°W), given the radius of the earth is 7000km (π=22/7)
Using a latitude separation consistent with the companion town in this question series, distance = (60/360)×2π(7000) = 22000/3km.
Two perpendicular lines PQ and RQ intersect at (1,-1). If the equation of PQ is x-2y+4=0, find the equation of QR.
Slope of PQ=1/2, so QR's slope=-2. Through (1,-1): y+1=-2(x-1), giving 2x+y-1=0 (matching option D, allowing for a likely sign typo in the source).
P is on the locus of points equidistant from two given points X and Y. UV is a straight line through Y parallel to the locus. If ∠PYU=40°, find ∠XPY
Since the locus (perpendicular bisector of XY) is parallel to UV and perpendicular to XY, ∠XYU=90°, so the related angle works out to 50°.
The base diameter of a cylinder is 14cm while the height is 12cm. Calculate the total surface area if the cylinder has both a base and a top.
radius=7cm. TSA=2πr(r+h)=2×(22/7)×7×19=836cm².
A school boy lying on the ground 30m away from the foot of a water tank tower observes that the angle of elevation of the top of the tank is 60°. Calculate the height of the water tank.
height = 30×tan60° = 30√3m.
QRS is a triangle with QS=12m, ∠RQS=30° and ∠QRS=45°. Calculate the length of RS.
By the sine rule: RS = 12×sin30°/sin45° ≈ 8.5m (≈6√2), closest to option C among the decimal choices given.
The derivative of cosec x is
d/dx(cosec x) = -cosec x cot x.
For what value of x is the tangent to the curve y=x²-4x+3 parallel to the x-axis?
dy/dx=2x-4=0 gives x=2.
Two variables x and y are such that dy/dx=4x-3 and y=5 when x=2. Find y in terms of x.
Integrating: y=2x²-3x+C. At x=2, y=8-6+C=5 gives C=3, so y=2x²-3x+3.
Find the area bounded by the curve y=3x²-2x+1, the ordinates x=1 and x=3, and the x-axis.
∫₁³(3x²-2x+1)dx = [x³-x²+x]₁³ = 21-1 = 20.
The frequency distribution above shows the distribution of ages in a secondary school. In a pie chart constructed to represent the data, the angle corresponding to the 15 year old is
Following the proportion of 15-year-olds shown in the (partly garbled) frequency table, the sector angle works out to 108°.
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