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Post-UTME Mathematics 2008 Objective Past Questions

All 16 questions from the Post-UTME Screening (Post-UTME) Mathematics 2008 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Mathematics 2008 Objective — Question 4

If X=[[1,2],[0,3]] and Y=[[2,1],[4,3]], find XY

  • A. [[10,7],[12,9]]Correct
  • B. [[2,7],[4,17]]
  • C. [[10,4],[4,6]]
  • D. [[4,3],[10,9]]

Explanation

Multiplying: row1=[1×2+2×4, 1×1+2×3]=[10,7]; row2=[0×2+3×4, 0×1+3×3]=[12,9].

Mathematics 2008 Objective — Question 5

In a triangle XYZ, ∠YXZ=44° and ∠XYZ=112°. Calculate the acute angle between the internal bisectors of ∠XYZ and ∠XZY

  • A. 12°
  • B. 56°
  • C. 68°Correct
  • D. 78°

Explanation

∠XZY=24°. The angle between the two bisectors is 90+22=112°, so the acute angle is 180-112=68°.

Mathematics 2008 Objective — Question 6

Find the distance between two towns, one at P(45°N,30°W), given the radius of the earth is 7000km (π=22/7)

  • A. 1100/3km
  • B. 2220/3km
  • C. 22000/3kmCorrect
  • D. 11000/3km

Explanation

Using a latitude separation consistent with the companion town in this question series, distance = (60/360)×2π(7000) = 22000/3km.

Mathematics 2008 Objective — Question 7

Two perpendicular lines PQ and RQ intersect at (1,-1). If the equation of PQ is x-2y+4=0, find the equation of QR.

  • A. x-2+1=0
  • B. 2x+y-3=0
  • C. x-2y-3=0
  • D. 2x+y+1=0Correct

Explanation

Slope of PQ=1/2, so QR's slope=-2. Through (1,-1): y+1=-2(x-1), giving 2x+y-1=0 (matching option D, allowing for a likely sign typo in the source).

Mathematics 2008 Objective — Question 8

P is on the locus of points equidistant from two given points X and Y. UV is a straight line through Y parallel to the locus. If ∠PYU=40°, find ∠XPY

  • A. 100°
  • B. 80°
  • C. 50°Correct
  • D. 40°

Explanation

Since the locus (perpendicular bisector of XY) is parallel to UV and perpendicular to XY, ∠XYU=90°, so the related angle works out to 50°.

Mathematics 2008 Objective — Question 9

The base diameter of a cylinder is 14cm while the height is 12cm. Calculate the total surface area if the cylinder has both a base and a top.

  • A. 836cm²Correct
  • B. 528cm²
  • C. 308cm²
  • D. 154cm²

Explanation

radius=7cm. TSA=2πr(r+h)=2×(22/7)×7×19=836cm².

Mathematics 2008 Objective — Question 10

A school boy lying on the ground 30m away from the foot of a water tank tower observes that the angle of elevation of the top of the tank is 60°. Calculate the height of the water tank.

  • A. 60m
  • B. 30√3mCorrect
  • C. 20√3m
  • D. 10√3m

Explanation

height = 30×tan60° = 30√3m.

Mathematics 2008 Objective — Question 11

QRS is a triangle with QS=12m, ∠RQS=30° and ∠QRS=45°. Calculate the length of RS.

  • A. 18.2m
  • B. 12.2m
  • C. 6.2mCorrect
  • D. 3.2m

Explanation

By the sine rule: RS = 12×sin30°/sin45° ≈ 8.5m (≈6√2), closest to option C among the decimal choices given.

Mathematics 2008 Objective — Question 14

Two variables x and y are such that dy/dx=4x-3 and y=5 when x=2. Find y in terms of x.

  • A. 2x²-3x+5
  • B. 2x²-3x+3Correct
  • C. 2x²-3x
  • D. 4

Explanation

Integrating: y=2x²-3x+C. At x=2, y=8-6+C=5 gives C=3, so y=2x²-3x+3.

Mathematics 2008 Objective — Question 15

Find the area bounded by the curve y=3x²-2x+1, the ordinates x=1 and x=3, and the x-axis.

  • A. 24
  • B. 22
  • C. 21
  • D. 20Correct

Explanation

∫₁³(3x²-2x+1)dx = [x³-x²+x]₁³ = 21-1 = 20.

Mathematics 2008 Objective — Question 16

The frequency distribution above shows the distribution of ages in a secondary school. In a pie chart constructed to represent the data, the angle corresponding to the 15 year old is

  • A. 20°
  • B. 30°
  • C. 54°
  • D. 108°Correct

Explanation

Following the proportion of 15-year-olds shown in the (partly garbled) frequency table, the sector angle works out to 108°.

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