Post-UTME Mathematics 2013 Objective — Question 68
Question 68 of 100 from the Post-UTME Screening (Post-UTME) Mathematics 2013 Objective paper, with the correct answer and a full explanation.
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Given that Tanθ=3/4 and θ is in the second quadrant, find sin2θ
- A. -2/35
- B. 30.78
- C. -24/25Correct
- D. 18
Explanation
Using the 3-4-5 triangle with sinθ=3/5 and cosθ=-4/5 (Q2): sin2θ=2sinθcosθ=2(3/5)(-4/5)=-24/25.
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