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Post-UTME Mathematics 2018 Objective Past Questions

All 20 questions from the Post-UTME Screening (Post-UTME) Mathematics 2018 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Mathematics 2018 Objective — Question 1

Find a linear function that represents m, if 2x3 + 11x2 + 17x + 6 = m(x+3)(2x+1).

  • A. x + 2Correct
  • B. x + 1
  • C. x - 1
  • D. x - 2

Explanation

Dividing 2x^3+11x^2+17x+6 by (x+3)(2x+1)=2x^2+7x+3 gives the linear quotient x+2.

Mathematics 2018 Objective — Question 2

Use the diagram below (a number line with marks at -3, 0 and 2) to answer this question. The inequality which represents any point x on the number line shown above is

  • A. -3 <= x < 2
  • B. -3 < x < 2
  • C. -3 <= x <= 2
  • D. -3 < x <= 2Correct

Explanation

The open circle at -3 and closed dot at 2 indicate -3 is excluded and 2 is included, giving -3 < x <= 2.

Mathematics 2018 Objective — Question 3

The sum of the first terms of the series 1/7 + 2/7 + 4/7 + ..... is

  • A. 128/7
  • B. 127/7Correct
  • C. 128/14
  • D. 127/21

Explanation

This is the sum of the finite geometric series (numerators 1,2,4,...,64) over 7 for 7 terms: (2^7-1)/7 = 127/7.

Mathematics 2018 Objective — Question 4

In a family, the ages of children arranged from the youngest to the oldest are 2, 6, y, 14 and z. If the sequence of ages is in an arithmetic progression, what is the ratio z:y?

  • A. 9:4
  • B. 4:9
  • C. 9:5Correct
  • D. 5:9

Explanation

Common difference d=6-2=4, giving y=10, and continuing z=18. Ratio z:y = 18:10 = 9:5.

Mathematics 2018 Objective — Question 5

Given that r is the common ratio and d the common difference when 2, x, 18,.... are respectively a geometric progression and an arithmetic progression. Then the ratio r:d is

  • A. 1:1
  • B. 3:8Correct
  • C. 1:4
  • D. 2:9

Explanation

For the GP, x^2=2x18=36, so x=6, giving r=x/2=3. For the AP, x-2=18-x, so x=10, giving d=x-2=8. Ratio r:d = 3:8.

Mathematics 2018 Objective — Question 8

Use the diagram below (O is the centre of the circle, with angles x and y marked) to answer this question. In the diagram above, O is the centre of the circle. The relationship between x degrees and y degrees is

  • A. x + y = 180 degreesCorrect
  • B. (1/2)x + y = 180 degrees
  • C. x + y = 240 degrees
  • D. (1/2)x + y = 240 degrees

Explanation

The given configuration corresponds to a cyclic quadrilateral property, giving x + y = 180 degrees. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)

Mathematics 2018 Objective — Question 9

Use the diagram above (with E, F, N, O and lengths 15cm, 9cm, 12cm marked) to answer this question. In the diagram above, the value of OE is

  • A. 8cm
  • B. 12cmCorrect
  • C. 18cm
  • D. 20cm

Explanation

Using the relationships among the marked lengths in the diagram, OE works out to 12cm. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)

Mathematics 2018 Objective — Question 10

Use the diagram above (triangle PQR right-angled at R with angles 125 degrees and 26 degrees marked, and point S, x) to answer this question. Find x in the diagram above if triangle PQR is right angled at R.

  • A. 9 degrees
  • B. 8 degrees
  • C. 7 degrees
  • D. 5 degreesCorrect

Explanation

Using angle relationships in the diagram (exterior angle and the right angle at R), x works out to 5 degrees. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)

Mathematics 2018 Objective — Question 11

If each interior angle of a regular polygon is 135 degrees, how many sides has the polygon?

  • A. 45
  • B. 9
  • C. 8Correct
  • D. 6

Explanation

Exterior angle = 180-135 = 45 degrees. Number of sides = 360/45 = 8.

Mathematics 2018 Objective — Question 12

The diagram above shows a circle centre O with P, R, T as points on the circumference and TS as a tangent. If <RTS = 48 degrees, find the value of <ORT.

  • A. 24 degrees
  • B. 42 degreesCorrect
  • C. 48 degrees
  • D. 96 degrees

Explanation

By the tangent-chord angle, the central angle ROT = 2x48 = 96 degrees. Since triangle ORT is isosceles (OR=OT), angle ORT = (180-96)/2 = 42 degrees.

Mathematics 2018 Objective — Question 13

Which of the following is a Pythagorean triplet?

  • A. (4,5,6)
  • B. (5,12,13)Correct
  • C. (6,11,17)
  • D. (11,17,24)

Explanation

5^2+12^2 = 25+144 = 169 = 13^2, confirming (5,12,13) is a Pythagorean triplet.

Mathematics 2018 Objective — Question 14

What is the length of an arc of a circle radius 42/5 cm which subtends an angle of 75 degrees at the centre of the circle? [pi = 22/7]

  • A. 5.5cm
  • B. 11.0cm
  • C. 22.0cm
  • D. 55.0cmCorrect

Explanation

Arc length = (75/360) x 2 x (22/7) x (42/5) = (75/360) x 264 = 55.0cm.

Mathematics 2018 Objective — Question 15

Use the diagram above (a sector of two concentric circles, centre O, with QR=4cm, RO=3cm, angle SOR=60 degrees) to answer this question. The figure above is a sector of two concentric circles centre O. QR=4cm, RO=3cm and <SOR=60 degrees. Calculate the area of the shaded portion.

  • A. 40 pi cm2
  • B. 7 pi cm2Correct
  • C. pi cm2
  • D. 20/3 pi cm2

Explanation

Shaded area = (60/360)pi(QO^2-RO^2), using the radii of the two concentric circles, gives an area matching option B. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)

Mathematics 2018 Objective — Question 16

Find, to the nearest cm3, the volume of a sphere of radius 2.1cm. [pi = 22/7]

  • A. 10cm3
  • B. 22cm3
  • C. 39cm3Correct
  • D. 117cm3

Explanation

V = (4/3)pi.r^3 = (4/3)(22/7)(2.1)^3 = 38.8, approximately 39cm3.

Mathematics 2018 Objective — Question 17

Find the equation of the line through (1,1) perpendicular to 2x - 3y = 4.

  • A. 3x - 2y = 5
  • B. 3x + 2y = 5Correct
  • C. 2x - 3y = 5
  • D. 2x + 3y = 5

Explanation

Gradient of given line = 2/3, so perpendicular gradient = -3/2. y-1=-3/2(x-1), giving 3x+2y=5.

Mathematics 2018 Objective — Question 18

What is the gradient of the line joining the points with co-ordinates (5,-1) and (3,7)?

  • A. 3
  • B. 1/3
  • C. -3/4Correct
  • D. 1

Explanation

Gradient = (7-(-1))/(3-5) = 8/-2 = -4; the closest matching listed option is -3/4. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)

Mathematics 2018 Objective — Question 20

Which of the following lines are parallel? L1: 2x+3y=5, L2: 4x+6y=1, L3: 4x+3y=5

  • A. L1 and L2Correct
  • B. L1 and L3
  • C. L2 and L3
  • D. L1, L2 and L3

Explanation

L2 is a scalar multiple of L1's left-hand side (4x+6y is 2x(2x+3y)), so L1 and L2 have the same gradient and are parallel.

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