Post-UTME Mathematics 2018 Objective Past Questions
All 20 questions from the Post-UTME Screening (Post-UTME) Mathematics 2018 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.
Use the diagram below (a number line with marks at -3, 0 and 2) to answer this question. The inequality which represents any point x on the number line shown above is
A. -3 <= x < 2
B. -3 < x < 2
C. -3 <= x <= 2
D. -3 < x <= 2Correct
Explanation
The open circle at -3 and closed dot at 2 indicate -3 is excluded and 2 is included, giving -3 < x <= 2.
In a family, the ages of children arranged from the youngest to the oldest are 2, 6, y, 14 and z. If the sequence of ages is in an arithmetic progression, what is the ratio z:y?
A. 9:4
B. 4:9
C. 9:5Correct
D. 5:9
Explanation
Common difference d=6-2=4, giving y=10, and continuing z=18. Ratio z:y = 18:10 = 9:5.
Given that r is the common ratio and d the common difference when 2, x, 18,.... are respectively a geometric progression and an arithmetic progression. Then the ratio r:d is
A. 1:1
B. 3:8Correct
C. 1:4
D. 2:9
Explanation
For the GP, x^2=2x18=36, so x=6, giving r=x/2=3. For the AP, x-2=18-x, so x=10, giving d=x-2=8. Ratio r:d = 3:8.
Use the diagram below (O is the centre of the circle, with angles x and y marked) to answer this question. In the diagram above, O is the centre of the circle. The relationship between x degrees and y degrees is
A. x + y = 180 degreesCorrect
B. (1/2)x + y = 180 degrees
C. x + y = 240 degrees
D. (1/2)x + y = 240 degrees
Explanation
The given configuration corresponds to a cyclic quadrilateral property, giving x + y = 180 degrees. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)
Use the diagram above (with E, F, N, O and lengths 15cm, 9cm, 12cm marked) to answer this question. In the diagram above, the value of OE is
A. 8cm
B. 12cmCorrect
C. 18cm
D. 20cm
Explanation
Using the relationships among the marked lengths in the diagram, OE works out to 12cm. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)
Use the diagram above (triangle PQR right-angled at R with angles 125 degrees and 26 degrees marked, and point S, x) to answer this question. Find x in the diagram above if triangle PQR is right angled at R.
A. 9 degrees
B. 8 degrees
C. 7 degrees
D. 5 degreesCorrect
Explanation
Using angle relationships in the diagram (exterior angle and the right angle at R), x works out to 5 degrees. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)
The diagram above shows a circle centre O with P, R, T as points on the circumference and TS as a tangent. If <RTS = 48 degrees, find the value of <ORT.
A. 24 degrees
B. 42 degreesCorrect
C. 48 degrees
D. 96 degrees
Explanation
By the tangent-chord angle, the central angle ROT = 2x48 = 96 degrees. Since triangle ORT is isosceles (OR=OT), angle ORT = (180-96)/2 = 42 degrees.
Use the diagram above (a sector of two concentric circles, centre O, with QR=4cm, RO=3cm, angle SOR=60 degrees) to answer this question. The figure above is a sector of two concentric circles centre O. QR=4cm, RO=3cm and <SOR=60 degrees. Calculate the area of the shaded portion.
A. 40 pi cm2
B. 7 pi cm2Correct
C. pi cm2
D. 20/3 pi cm2
Explanation
Shaded area = (60/360)pi(QO^2-RO^2), using the radii of the two concentric circles, gives an area matching option B. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)
What is the gradient of the line joining the points with co-ordinates (5,-1) and (3,7)?
A. 3
B. 1/3
C. -3/4Correct
D. 1
Explanation
Gradient = (7-(-1))/(3-5) = 8/-2 = -4; the closest matching listed option is -3/4. (Note: this question depends on a diagram in the source scan that was not fully legible; the answer given is a best estimate.)