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Post-UTME Mathematics 2019 Objective — Question 32

Question 32 of 50 from the Post-UTME Screening (Post-UTME) Mathematics 2019 Objective paper, with the correct answer and a full explanation.

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Change 71 (base 10) to base 8

  • A. 107₈Correct
  • B. 106₈
  • C. 71₈
  • D. 17₈

Explanation

71 = 8x8+7, remainder 7, then 1 more group: 71 = 1(64)+0(8)+7 = 107 in base 8.

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