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Post-UTME Physics 2016 Objective Past Questions

All 20 questions from the Post-UTME Screening (Post-UTME) Physics 2016 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Physics 2016 Objective — Question 1

When a rocket at a high altitude passes overhead, only a little sound is heard from it because

  • A. the rocket produces little sound at high altitudes
  • B. the atmosphere absorbs most of the soundCorrect
  • C. light travels faster than sound
  • D. the rocket exhaust absorbs the sound

Explanation

As sound travels up through the atmosphere from a high-altitude rocket, much of its energy is absorbed/scattered by the atmosphere before reaching an observer on the ground.

Physics 2016 Objective — Question 2

What causes musical notes produced from open pipes to be sharper than those from closed pipes is the

  • A. size of the pipes
  • B. difference in intensities
  • C. variation of pitches
  • D. number of overtonesCorrect

Explanation

Open pipes produce both odd and even harmonics (overtones), including a fundamental twice the frequency of an equivalent closed pipe, giving a sharper (higher pitch) sound; closed pipes produce only odd harmonics.

Physics 2016 Objective — Question 3

The optical device labelled X in the diagram (light rays converging through F to C) is a

  • A. converging mirrorCorrect
  • B. diverging mirror
  • C. converging lens
  • D. diverging lens

Explanation

The labels F (focal point) and C (centre of curvature) both being used together, with rays converging after reflecting, indicate a converging (concave) mirror rather than a lens.

Physics 2016 Objective — Question 4

A sinusoidal wave travelling along a string is described by the equation y = 30 sin[15*pi(4t-2x)]. What is the wavelength of this wave if t is in seconds and x is in metres?

  • A. 30.0cm
  • B. 60.0cm
  • C. 3.0cm
  • D. 6.7cmCorrect

Explanation

Expanding: y = 30 sin(60*pi*t - 30*pi*x). Comparing to y=A sin(wt-kx), k = 30*pi. Wavelength = 2*pi/k = 2*pi/(30*pi) = 1/15 m = 0.067m = 6.7cm.

Physics 2016 Objective — Question 5

A ray of light travels up through a bucket of water of refractive index 1.33. If the angle of incidence is 50 degrees at the surface, the ray experiences

  • A. total internal reflectionCorrect
  • B. total refraction
  • C. partial reflection
  • D. partial refraction

Explanation

Critical angle = arcsin(1/1.33) = 48.8 degrees. Since the angle of incidence (50 degrees) exceeds the critical angle, total internal reflection occurs.

Physics 2016 Objective — Question 6

Calculate the frequency of the first overtone of a closed pipe of length 68.0cm if the velocity of sound in air is 340.0 m/s.

  • A. 667Hz
  • B. 375HzCorrect
  • C. 400Hz
  • D. 520Hz

Explanation

A closed pipe supports only odd harmonics. The fundamental f1 = v/4L = 340/(4x0.68) = 125Hz. The first overtone is the next allowed harmonic, the 3rd harmonic: f3 = 3 x 125 = 375Hz.

Physics 2016 Objective — Question 7

In wind instruments, sound is produced as a result of the vibration of

  • A. metal rods
  • B. stretched strings
  • C. air columnsCorrect
  • D. stretched membranes

Explanation

Wind instruments produce sound through the vibration of air columns inside the instrument.

Physics 2016 Objective — Question 8

Calculate the focal length of a converging lens which forms a real image of magnification 4 when the object distance is 15cm.

  • A. 12cmCorrect
  • B. 10cm
  • C. 20cm
  • D. 16cm

Explanation

For a real image, v = m x u = 4 x 15 = 60cm. Using 1/f = 1/v + 1/u = 1/60 + 1/15 = 1/60 + 4/60 = 5/60 = 1/12, so f = 12cm.

Physics 2016 Objective — Question 9

Diagram: light rays pass through an aperture past an opaque globe (with measurements 6cm, 4cm, 2cm) towards a screen at distance x. From the diagram, what is the distance x if there is no shadow of the globe on the screen?

  • A. 4.0cm
  • B. 6.0cm
  • C. 3.0cmCorrect
  • D. 5.0cm

Explanation

Using similar triangles based on the geometry of the light source, aperture, and globe (so that the penumbra regions from each edge of the source exactly meet with no umbra reaching the screen), the distance works out to approximately 3.0cm. (Note: precise figure dimensions were only partially legible in the scan.)

Physics 2016 Objective — Question 10

A point source in space produces wave fronts whose shapes are

  • A. elliptical
  • B. conical
  • C. circular
  • D. sphericalCorrect

Explanation

A point source radiates energy equally in all directions in 3D space, producing spherical wavefronts.

Physics 2016 Objective — Question 11

A bullet is fired from a point P with an initial velocity of 50 ms-1 at an angle of 45 degrees to the horizontal. At what distance from the point P will the bullet hit the ground assuming that the ground is horizontal throughout the trajectory. (Take g = 10ms-2)

  • A. 125m
  • B. 175m
  • C. 200m
  • D. 250mCorrect

Explanation

Range = v^2.sin(2theta)/g = 50^2 x sin(90)/10 = 2500/10 = 250m.

Physics 2016 Objective — Question 12

Calculate the force on an electron situated in a uniform electric field of intensity 120 000Vm-1

  • A. 2.25 x 10^-11N
  • B. 3.61 x 10^-10N
  • C. 1.92 x 10^-14NCorrect
  • D. 3.75 x 10^-14N

Explanation

F = qE = 1.6x10^-19 x 120000 = 1.92x10^-14N.

Physics 2016 Objective — Question 13

A current of 5A flowing in a circuit falls to zero in 0.1 sec. If the average e.m.f of 200V is induced, what is the self-inductance of the circuit?

  • A. 5
  • B. 4Correct
  • C. 40
  • D. 20

Explanation

emf = L(dI/dt). L = emf/(dI/dt) = 200/(5/0.1) = 200/50 = 4H.

Physics 2016 Objective — Question 14

Use the diagram above (an AC circuit with 120V, 60/pi Hz supply, a resistor R and capacitor C = 30uF) to answer this question. In the circuit above, calculate the reactance of the capacitor.

  • A. 36.14 ohm
  • B. 88.42 ohm
  • C. 277.78 ohmCorrect
  • D. 360.05 ohm

Explanation

Xc = 1/(2.pi.f.C) = 1/(2 x 60 x 30x10^-6) = 277.78 ohm (using f=60/pi so that 2.pi.f=120).

Physics 2016 Objective — Question 15

A step-down transformer reduces the voltage from 2400V to 120V. If the primary winding has 4000 turns, determine the number of turns in the secondary winding.

  • A. 200.0 turnsCorrect
  • B. 9.8 turns
  • C. 240.0 turns
  • D. 20.0 turns

Explanation

Ns = Np x Vs/Vp = 4000 x 120/2400 = 200 turns.

Physics 2016 Objective — Question 16

I. Travel in straight lines II. Have kinetic energy III. produce heat on collision with metals IV. Can be deflected by a magnetic field. From the above, which of the combinations is a characteristic of cathode rays?

  • A. I, II and IV only
  • B. I, II, III and IVCorrect
  • C. II and IV only
  • D. I and II only

Explanation

Cathode rays travel in straight lines, possess kinetic energy, produce heat on collision, and can be deflected by magnetic fields - all four properties apply.

Physics 2016 Objective — Question 17

A coil having an inductance of 0.14H and a resistance of 12 ohm is connected across a 110V, 25Hz line. Determine the current in the coil.

  • A. 4.4ACorrect
  • B. 5.4A
  • C. 2.5A
  • D. 1.2A

Explanation

XL=2.pi.f.L=2x3.14x25x0.14=22 ohm. Z=sqrt(R^2+XL^2)=sqrt(144+484)=25.06 ohm. I=V/Z=110/25.06=4.4A.

Physics 2016 Objective — Question 18

What is the time required to electroplate 3.00g of silver onto a brass casting by using a steady current of 15.0A? [e.c.e. of silver = 0.001118gC-1]

  • A. 50.01s
  • B. 85.21s
  • C. 178.89sCorrect
  • D. 45.00s

Explanation

t = mass/(e.c.e. x I) = 3.00/(0.001118x15) = 178.89s.

Physics 2016 Objective — Question 19

The electron diffraction experiment illustrates

  • A. the wave property of matterCorrect
  • B. the particle property of matter
  • C. that matter exists
  • D. that matter is indestructible.

Explanation

Electron diffraction demonstrates that particles (electrons) exhibit wave-like properties.

Physics 2016 Objective — Question 20

An induced e.m.f. is obtained between the ends of a horizontal steel axle of a moving train because the

  • A. steel axle moves parallel to the earth's field
  • B. steel axle is a conductor
  • C. earth's magnetic field has a horizontal component
  • D. earth has a vertical magnetic field componentCorrect

Explanation

The vertical component of the earth's magnetic field, combined with the horizontal motion of the conducting axle, induces an emf across it.

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