Post-UTME Physics 2019 Objective — Question 14
Question 14 of 20 from the Post-UTME Screening (Post-UTME) Physics 2019 Objective paper, with the correct answer and a full explanation.
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An object 2.0 cm high is placed 20cm from a converging lens of focal length 15cm. Calculate the height of the image formed.
- A. 2.67 cm
- B. 3.00cm
- C. 6.00cmCorrect
- D. 60.00cm
Explanation
Using 1/v = 1/f + 1/u (sign convention): 1/v = 1/15-1/20 = 1/60, so v=60cm. Magnification = 60/20 = 3. Image height = 3x2 = 6.00cm.
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