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JAMB Chemistry 2007 Objective — Question 22

Question 22 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2007 Objective paper, with the correct answer and a full explanation.

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How long would it take to deposit 0.08g of copper from CuCl2 solution by passing a current of 0.5A? [Cu=64, F=96500 C/mol]

  • A. 48 mins
  • B. 24 mins
  • C. 8 minsCorrect
  • D. 6 mins

Explanation

Cu2+ + 2e- -> Cu: 64g needs 2x96500C, so 0.08g needs (2x96500x0.08)/64 = 241.25C. t=Q/I=241.25/0.5=482.5s = about 8 minutes.

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