JAMB Chemistry 2009 Objective — Question 24

Question 24 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2009 Objective paper, with the correct answer and a full explanation.

What current will deposit 3.25g of zinc in 2 hrs?

A. 3.25A
B. 2.00A
C. 1.34ACorrect
D. 0.67A

Explanation

1mole of Zn (65g) takes 2F (2 x 96500C). Then, 3.25g will require (2x96500/65 x 3.25)C = 9650C. Q=It. t=2hrs=(2x3600)s=7200s. I=Q/t=9650/7200=1.34A. [Zn=65, F=96500C]

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