JAMB Chemistry 2014 Objective — Question 14
Question 14 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2014 Objective paper, with the correct answer and a full explanation.
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Mass of Pb(NO₃)₂ = 16.55g. Given Mass of H₂O = 100g, taking the density of water as 1gcm⁻³ (volume of water = 100cm³ = 0.1dm³), calculate the solubility of Pb(NO₃)₂.
- A. 0.50moldm⁻³
- B. 0.16.55
- C. 0.5modm⁻³Correct
- D. 16.55g
Explanation
Molar mass of Pb(NO3)2 = 331gmol⁻¹. Mole of Pb(NO3)2 = 16.55g/331gmol⁻¹ = 0.05mol. Solubility = Conc. = Mole/Volume(dm³) = 0.05mol/0.1dm³ = 0.5moldm⁻³.
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