JAMB Chemistry 2014 Objective — Question 21

Question 21 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2014 Objective paper, with the correct answer and a full explanation.

Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s). In the reaction above, the oxidation number of the reducing agent changes from

A. 0 to +2Correct
B. 0 to +4
C. +2 to 0
D. +4 to +2

Explanation

Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s). The reducing agent is zinc, since it undergoes oxidation. Its oxidation number increases from zero to +2.

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