JAMB Chemistry 2014 Objective — Question 23

Question 23 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2014 Objective paper, with the correct answer and a full explanation.

Calculate the quantity of electricity required to liberate 10g of copper from a copper compound.

A. 15196.5Correct
B. 32395.5
C. 30156.3
D. 60784.5

Explanation

Q = It = 2 × (60×60)s = 7200C. For 1mole of Cu(64g), 2F(193000C) of electricity will be required. Thus 72000C will produce (64g/193000C)×7200C = 2.39g... For 10g copper: [Cu=64, F=96500Cmol⁻¹], Q required = (10/64)×2×96500 ≈ 15196.5C.

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