JAMB Chemistry 2014 Objective — Question 3
Question 3 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2014 Objective paper, with the correct answer and a full explanation.
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A gas X diffuses twice as fast as gas Y. If the relative molecular mass of X is 32, calculate the relative molecular mass of Y.
- A. 64
- B. 128Correct
- C. 8
- D. 16
Explanation
Using Graham's law: Rx/Ry = √(RMMy/RMMx). Rx=2Ry: (2Ry/Ry)² = RMMy/32, so 4 = RMMy/32, RMMy = 4×32 = 128.
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