JAMB Chemistry 2014 Objective — Question 8

Question 8 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2014 Objective paper, with the correct answer and a full explanation.

How many protons, neutrons and electrons respectively are present in the element 60 Co?

A. 27, 33, and 60
B. 27, 33 and 27Correct
C. 33, 27 and 27
D. 33, 27 and 33

Explanation

⁶⁰₂₇Co: P=27. Since electrons and protons are always equal in a neutral atom, E=27. M=P+N, 60=27+N, N=60−27=33.

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