JAMB Chemistry 2018 Objective — Question 19

Question 19 of 36 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2018 Objective paper, with the correct answer and a full explanation.

An alkanoic acid has molecular mass of 88. Its molecular formula is

A. C₄H₈COOH
B. C₂H₅COOH
C. C₃H₇COOHCorrect
D. C₃H₅COOH

Explanation

The general formula of alkanoic acids is CₙH₂ₙ₊₁COOH. Solving 12n+2n+1+12+16+16+1=88 gives n=3, so the formula is C₃H₇COOH.

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