JAMB Chemistry 2018 Objective — Question 29
Question 29 of 36 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2018 Objective paper, with the correct answer and a full explanation.
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¹³₇F + X → ²²₁₁Na + ⁴₂n. In the equation above, X is
- A. ¹₁PCorrect
- B. ⁰₁n
- C. ²₁₂H
- D. ⁴₂He
Explanation
Balancing mass and atomic numbers on both sides of the nuclear equation identifies X as a proton, ¹₁P.
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