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JAMB Chemistry 2019 Objective — Question 12

Question 12 of 40 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2019 Objective paper, with the correct answer and a full explanation.

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A gas X diffuses twice as fast as a gas Y. If the relative molecular mass of Y is 112, calculate the relative molecular mass of X

  • A. 28Correct
  • B. 14
  • C. 56
  • D. 120

Explanation

By Graham's law: dₓ/dᵧ = √(R.M.Mᵧ/R.M.Mₓ). Given dₓ=2dᵧ: 2 = √(112/R.M.Mₓ) ⇒ 4 = 112/R.M.Mₓ ⇒ R.M.Mₓ = 112/4 = 28.

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