JAMB Chemistry 2019 Objective — Question 38
Question 38 of 40 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2019 Objective paper, with the correct answer and a full explanation.
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If the solubility of a salt at 25°C is 45g per 1000g of water, how much of the salt can be obtained from 50g of the (saturated) solution?
- A. 2.25g
- B. 20g
- C. 45g
- D. 2.15gCorrect
Explanation
Mass of saturated solution = mass of solute + mass of solvent = 45+1000 = 1045g, which contains 45g of solute. Mass of solute obtainable from 50g of solution = (45/1045)×50 ≈ 2.153g.
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