JAMB Chemistry 2020 Objective — Question 39
Question 39 of 40 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2020 Objective paper, with the correct answer and a full explanation.
Advertisement
39. If 24.83cm3 of 0.15moldm-3 NaOH is titrated to its end point with 39.45cm3 of HCl, the concentration of HCl in moldm-3 is
- A. A. 0.094Correct
- B. B. 1.5
- C. C. 0.15
- D. D. 0.94
Explanation
Moles NaOH = 0.15 x 0.02483 = 0.003725mol. For a 1:1 reaction with HCl, concentration of HCl = 0.003725/0.03945 ≈ 0.094moldm-3.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.