JAMB Chemistry 2021 Objective — Question 2
Question 2 of 41 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2021 Objective paper, with the correct answer and a full explanation.
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3.56 g of CuSO₄·xH₂O is heated in a crucible until a constant mass of 3.20 g is obtained. Determine the value of x.
- A. 1Correct
- B. 2
- C. 3
- D. 4
Explanation
Mass of H₂O = 3.56 − 3.20 = 0.36 g. CuSO₄/H₂O mole ratio: (3.20/160) : (0.36/18) = 0.02 : 0.02 = 1:1. Therefore x = 1, formula is CuSO₄·H₂O.
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