JAMB Mathematics 2018 Objective — Question 37
Question 37 of 39 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2018 Objective paper, with the correct answer and a full explanation.
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Determine the maximum value of y=3x²−x³
- A. 5
- B. 4Correct
- C. 2
- D. 0
Explanation
dy/dx=6x−3x²=0 → x=0 or x=2. At x=2 (maximum, since d²y/dx²<0): y=3(4)−8=12−8=4.
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