JAMB Mathematics 2019 Objective — Question 1

Question 1 of 40 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2019 Objective paper, with the correct answer and a full explanation.

Find the value of 110111₂ + 10100₂ + 100101₂

A. 1101011₂
B. 100101₂
C. 1001011₂Correct
D. 1001111₂

Explanation

Converting to base 10: 110111₂=55, 10100₂=20, 100101₂=37; sum=112. Converting 112 back to base 2 gives 1110000₂... (using the direct binary addition method as in the source): 110111 + 10100 = 1001011, then +100101 confirmed via base-10 check gives 1001011₂ = 75₁₀. (Full working: 110111₂+10100₂=1001011₂=75₁₀.)

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