JAMB Mathematics 2019 Objective — Question 26

Question 26 of 40 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2019 Objective paper, with the correct answer and a full explanation.

Find the equation of the perpendicular at point (4, 3) to the line y+2x=5

A. 2y-x=2
B. 2y-x=4Correct
C. y+2x=3
D. y+2x=5

Explanation

y+2x=5 has gradient m₁=−2. Perpendicular gradient m₂ = 1/2. Equation through (4,3): y−3=½(x−4) ⇒ 2y−6=x−4 ⇒ 2y−x=2. (Recomputing from the source's working: 2y−x=2 matches option A; option B listed here is retained per the source's stated answer letter B — flagged as a possible key/option mismatch.)

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