JAMB Mathematics 2019 Objective — Question 30

Question 30 of 40 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2019 Objective paper, with the correct answer and a full explanation.

Determine the maximum value of y=3x²−x³

A. 0
B. 2
C. 4Correct
D. 6

Explanation

dy/dx=6x−3x²=0 ⇒ 3x(2−x)=0 ⇒ x=0 or x=2. Testing (or comparing y-values): at x=2, y=3(4)−8=4; at x=0, y=0. The maximum value is 4.

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