JAMB Mathematics 2021 Objective — Question 3

Question 3 of 40 from the Joint Admissions and Matriculation Board (JAMB) Mathematics 2021 Objective paper, with the correct answer and a full explanation.

3. Given that sec²θ + tan²θ = 3, what is the value of θ? (a) 30° (b) 60° (c) 45° (d) 90°

A. 30°
B. 60°
C. 45°Correct
D. 90°

Explanation

Since sec²θ = 1 + tan²θ, the equation becomes 1 + 2tan²θ = 3, so tan²θ = 1, tanθ = 1, giving θ = 45°.

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