JAMB Physics 2007 Objective — Question 23
Question 23 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2007 Objective paper, with the correct answer and a full explanation.
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E = Kq/r2 (E = electric field intensity, K = 1/(4.pi.e0), q = charge, r = distance). A charge 50uC has an electric field strength of 360NC-1 at a certain point. The electric field strength due to another charge 120uC kept at the same distance apart and in the same medium is
- A. 186NC-1
- B. 144NC-1
- C. 150NC-1
- D. 864NC-1Correct
Explanation
Since E is directly proportional to q: E1/q1 = E2/q2. 360/50 = E2/120, so E2 = 864NC-1.
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