JAMB Physics 2007 Objective — Question 26
Question 26 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2007 Objective paper, with the correct answer and a full explanation.
Advertisement
A 40kW electric cable is used to transmit electricity through a resistor of resistance 2.0 ohm at 800V. The power loss (internal energy) is
- A. 5.0x10^2 W
- B. 5.0x10^3 WCorrect
- C. 5.0x10^4 W
- D. 5.0x10^5 W
Explanation
I = P/V = 40,000/800 = 50A. Power loss = I2R = 50^2 x 2 = 5000W = 5.0x10^3 W.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.