JAMB Physics 2008 Objective — Question 47
Question 47 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2008 Objective paper, with the correct answer and a full explanation.
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47. Caesium has a work function of 3x10⁻¹⁹J. The maximum energy of liberated electrons when illuminated by light of frequency 6.7x10¹⁴Hz is [h=6.6x10⁻³⁴Js]
- A. 1.42x10⁻¹⁹JCorrect
- B. 3.00x10⁻¹⁹J
- C. 4.42x10⁻¹⁹J
- D. 7.42x10⁻¹⁹J
Explanation
E=hf=6.6x10⁻³⁴x6.7x10¹⁴=4.42x10⁻¹⁹J. Max KE = E - Wo = 4.42x10⁻¹⁹ - 3x10⁻¹⁹ = 1.42x10⁻¹⁹J.
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