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JAMB Physics 2009 Objective — Question 46

Question 46 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2009 Objective paper, with the correct answer and a full explanation.

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46. ¹⁴N + ⁴He → ¹⁷O + X. In the equation above, the particle X is

  • A. a protonCorrect
  • B. a neutron
  • C. an α-particle
  • D. a β-particle

Explanation

Balancing mass numbers: 14+4=17+a → a=1. Balancing atomic numbers: 7+2=8+b → b=1. So X is a proton.

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