JAMB Physics 2011 Objective — Question 25
Question 25 of 49 from the Joint Admissions and Matriculation Board (JAMB) Physics 2011 Objective paper, with the correct answer and a full explanation.
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A length of wire has a frequency of 255 Hz when stretched by a force of 225 N. If the force increases to 324 N, what is the new frequency of vibration?
- A. A. 488 Hz
- B. B. 356 Hz
- C. C. 306 HzCorrect
- D. D. 512 Hz
Explanation
Frequency f ∝ √F (tension), so f1/√F1 = f2/√F2. f2 = f1x√(F2/F1) = 255x√(324/225) = (255x18)/15 = 306Hz.
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