JAMB Physics 2011 Objective — Question 33
Question 33 of 49 from the Joint Admissions and Matriculation Board (JAMB) Physics 2011 Objective paper, with the correct answer and a full explanation.
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[Circuit: 2Ω, 4Ω and 12Ω resistors connected in parallel, and a 12V battery across the combination] The current flowing through the 12Ω resistor is
- A. A. 3.2A
- B. B. 9.6A
- C. C. 14.4A
- D. D. 1.0ACorrect
Explanation
When resistors are connected in parallel, the full 12V is across the 12Ω resistor. I = V/R = 12/12 = 1.0A.
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