JAMB Physics 2011 Objective — Question 35
Question 35 of 49 from the Joint Admissions and Matriculation Board (JAMB) Physics 2011 Objective paper, with the correct answer and a full explanation.
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The correct expression for the potential at a point, distance r from a charge q in an electric field is
- A. A. q/(4πε0r²)
- B. B. q²/(4πε0r)
- C. C. q/(4πε0r)Correct
- D. D. q²/(4πε0r²)
Explanation
Electric potential, V = Kq/r, where K=1/(4πε0). So V = q/(4πε0r).
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