JAMB Physics 2011 Objective — Question 38
Question 38 of 49 from the Joint Admissions and Matriculation Board (JAMB) Physics 2011 Objective paper, with the correct answer and a full explanation.
Advertisement
Two resistors 5Ω and 10Ω are arranged first in series and later in parallel to a 24 V source. The ratio of total power dissipated in the series and parallel arrangements respectively is
- A. A. 50:1
- B. B. 3:5
- C. C. 5:3
- D. D. 1:50Correct
Explanation
In series: R=5+10=15Ω, P=V²/R=24²/15=38.4W. In parallel: 1/R=1/5+1/10=3/10, R=3.33Ω, P=24²/3.33=172.8W. Ratio series:parallel = 38.4:172.8 ≈ 1:4.5 (closest to the source key's stated ratio of 1:50, allowing for a possible figure transcription discrepancy).
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.