JAMB Physics 2015 Objective — Question 10
Question 10 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2015 Objective paper, with the correct answer and a full explanation.
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A current of 20A flows through a cable whose resistance is 5Ω. Calculate the electric power dissipated.
- A. 2×10³WCorrect
- B. 2×10⁴W
- C. 1×10³W
- D. 1×10²W
Explanation
P = I²R = 20²×5 = 2000W = 2×10³W.
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