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JAMB Physics 2017 Objective — Question 17

Question 17 of 40 from the Joint Admissions and Matriculation Board (JAMB) Physics 2017 Objective paper, with the correct answer and a full explanation.

A stationary wave pattern is formed by a wave of frequency 40Hz and velocity 60cms⁻¹. What is the distance between adjacent nodes?

A. A. 0.33cm
B. B. 1.50cm
C. C. 0.67cm
D. D. 0.75cmCorrect

Explanation

λ=v/f=60/40=1.5cm; distance between adjacent nodes = λ/2 = 0.75cm.

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