JAMB Physics 2018 Objective — Question 16
Question 16 of 38 from the Joint Admissions and Matriculation Board (JAMB) Physics 2018 Objective paper, with the correct answer and a full explanation.
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The period of oscillation of a particle executing simple harmonic motion is 4π seconds. If the amplitude of oscillation is 3.0m, calculate the maximum speed of the particle
- A. 4.5m/s
- B. 1.5m/sCorrect
- C. 6m/s
- D. 0.17m/s
Explanation
ω = 2π/T = 2π/4π = 0.5rad/s. Vmax = ωA = 0.5×3 = 1.5m/s.
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