JAMB Physics 2018 Objective — Question 20
Question 20 of 38 from the Joint Admissions and Matriculation Board (JAMB) Physics 2018 Objective paper, with the correct answer and a full explanation.
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An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5°C per second, calculate the specific heat capacity of the liquid
- A. 5.1Jkg⁻¹K⁻¹
- B. 320Jkg⁻¹K⁻¹Correct
- C. 400Jkg⁻¹K⁻¹
- D. 111Jkg⁻¹K⁻¹
Explanation
Power = mcΔθ/t. Since Δθ/t is the given rate (2.5°C/s): 400 = 0.5×c×2.5 → c = 400/1.25 = 320Jkg⁻¹K⁻¹.
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