JAMB Physics 2018 Objective — Question 4

Question 4 of 38 from the Joint Admissions and Matriculation Board (JAMB) Physics 2018 Objective paper, with the correct answer and a full explanation.

A man starts with a velocity of 15m/s and moves with a uniform acceleration of 2m/s². What distance does he cover in the fifth second?

A. 100m
B. 76m
C. 176m
D. 24mCorrect

Explanation

Distance in 5th second = distance at t=5 minus distance at t=4. s(5)=15(5)+½(2)(25)=100m. s(4)=15(4)+½(2)(16)=76m. Distance in 5th second = 100−76 = 24m.

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