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JAMB Physics 2025 Objective Past Questions

All 40 questions from the Joint Admissions and Matriculation Board (JAMB) Physics 2025 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Physics 2025 Objective — Question 1

Which of the following is an example of a non-contact force?

  • A. friction
  • B. tension
  • C. gravitational forceCorrect
  • D. normal force

Explanation

Gravitational force acts at a distance without physical contact, unlike friction, tension, and normal force which require contact.

Physics 2025 Objective — Question 2

A body is projected vertically upward with a speed of 40 m/s. Calculate the maximum height reached. (g = 10 m/s²)

  • A. 80 mCorrect
  • B. 160 m
  • C. 200 m
  • D. 400 m

Explanation

Using v²=u²-2gh: 0=1600-20h → h=80 m.

Physics 2025 Objective — Question 3

A ray of light is incident at 30° on a surface with refractive index 1.5. What is the angle of refraction? (n_air=1)

  • A. 20°
  • B. 42°
  • C. 19.5°Correct
  • D. 22.6°

Explanation

Snell's law: sin θ₂=sin30°/1.5=0.3333 → θ₂≈19.5°.

Physics 2025 Objective — Question 4

A wire of length 10 m, cross-section 2 mm² has resistance 0.5 Ω. What is the resistivity?

  • A. 1×10⁻⁷ ΩmCorrect
  • B. 1.5×10⁻⁶ Ωm
  • C. 0.1 Ωm
  • D. 2.33×10⁻⁵ Ωm

Explanation

ρ=RA/l=(0.5×2×10⁻⁶)/10=1×10⁻⁷ Ωm.

Physics 2025 Objective — Question 5

A 0.2 kg block of ice at −10°C is heated until it melts. How much energy is required? (c_ice=2.1×10³ J/kg°C, L=3.3×10⁵ J/kg)

  • A. 66700 J
  • B. 4200 J
  • C. 70,200 JCorrect
  • D. 11500 J

Explanation

Q₁=mcΔθ=4200 J; Q₂=mL=66000 J; Total=70,200 J.

Physics 2025 Objective — Question 6

The displacement-time graph of a moving object is a straight line with positive slope. Which quantity is constant?

  • A. Displacement
  • B. velocityCorrect
  • C. acceleration
  • D. momentum

Explanation

Slope of displacement-time graph = velocity; a straight line means constant velocity.

Physics 2025 Objective — Question 7

A motorist at 20 ms⁻¹ sees a child 50 m ahead and decelerates at 5 ms⁻². The stopping distance is:

  • A. 10 m
  • B. 20 m
  • C. 40 mCorrect
  • D. 60 m

Explanation

v²=u²+2as → 0=400-10s → s=40 m.

Physics 2025 Objective — Question 8

Two forces 8 N and 6 N act at 60° to each other. The magnitude of their resultant is approximately:

Diagram for question 8
  • A. 10 N
  • B. 14 N
  • C. 12.2 NCorrect
  • D. 2 N

Explanation

R=√(8²+6²+2×8×6×cos60°)=√148≈12.2 N.

Physics 2025 Objective — Question 9

A 5 kg mass hangs from a spring balance in an elevator accelerating upward at 3 ms⁻². The balance reads:

  • A. 35 N
  • B. 50 N
  • C. 65 NCorrect
  • D. 80 N

Explanation

R=m(g+a)=5(10+3)=65 N.

Physics 2025 Objective — Question 10

A block of weight 20 N rests on an incline at 30°. The component of its weight parallel to the incline is:

  • A. 10 NCorrect
  • B. 20 N
  • C. √3 N
  • D. 0 N

Explanation

W∥=W sinθ=20×0.5=10 N.

Physics 2025 Objective — Question 11

A uniform metre rule of weight 1 N is pivoted at 20 cm. A 0.2 kg mass hangs at 0 cm. Where should a 0.3 kg mass be hung to balance it horizontally? (g=10 ms⁻²)

Diagram for question 11
  • A. 23 cm markCorrect
  • B. 60 cm mark
  • C. 81 cm mark
  • D. 36 cm mark

Explanation

Taking moments about pivot: 2×20+1×(x-20)=3×(x-20)+30 → x≈23.33 cm.

Physics 2025 Objective — Question 12

A 60 W lamp is on for 5 hours. The electrical energy consumed is:

  • A. 1.08×10⁶ JCorrect
  • B. 1.08×10⁵ J
  • C. 300 J
  • D. 3600 J

Explanation

E=Pt=60×5×3600=1.08×10⁶ J.

Physics 2025 Objective — Question 13

A steel wire 2 m long, cross-section 1.0 mm², Young's modulus 2×10¹¹ Nm⁻². Extension under 200 N load:

  • A. 0.5 mm
  • B. 2 mmCorrect
  • C. 10 mm
  • D. 20 mm

Explanation

e=FL/AY=(200×2)/(10⁻⁶×2×10¹¹)=2 mm.

Physics 2025 Objective — Question 14

In an ideal pulley system, a 400 N load is lifted 0.5 m by an effort moving 2.0 m. The mechanical advantage is:

  • A. 0.25
  • B. 4.0Correct
  • C. 1.5
  • D. 2.5

Explanation

MA=VR=2.0/0.5=4 (ideal system).

Physics 2025 Objective — Question 15

A glass block is completely immersed in water. The upthrust acting on it:

  • A. equals the weight of the block
  • B. equals the weight of displaced waterCorrect
  • C. is greater at the sides
  • D. acts horizontally

Explanation

Archimedes' principle: upthrust = weight of fluid displaced.

Physics 2025 Objective — Question 16

Water flows in a pipe of cross-section 4×10⁻⁴ m² at 5 ms⁻¹. Volume discharged in 1 minute:

  • A. 1.2×10⁻³ m³
  • B. 1.2×10⁻¹ m³Correct
  • C. 6×10⁻³ m³
  • D. 1.2×10⁻² m³

Explanation

V=Avt=4×10⁻⁴×5×60=0.12 m³=1.2×10⁻¹ m³.

Physics 2025 Objective — Question 17

A thermometer reads 10°C in ice and 90°C in steam. Actual temperature when it reads 50°C:

Diagram for question 17
  • A. 40°C
  • B. 50°CCorrect
  • C. 60°C
  • D. 75°C

Explanation

θ=((50-10)/(90-10))×100=50°C.

Physics 2025 Objective — Question 18

Steam at 100°C causes a more severe burn than water at 100°C because:

  • A. it depends on relative humidity
  • B. steam contains more latent heat per unit massCorrect
  • C. steam is at higher pressure
  • D. steam has higher thermal conductivity

Explanation

Steam releases additional latent heat of vaporisation (~2260 kJ/kg) when it condenses on skin.

Physics 2025 Objective — Question 19

In a gas, the root mean square speed of molecules is proportional to the:

  • A. absolute temperature
  • B. square root of absolute temperatureCorrect
  • C. cube of absolute temperature
  • D. reciprocal of absolute temperature

Explanation

v_rms=√(3RT/M) ∝ √T.

Physics 2025 Objective — Question 20

According to the first law of thermodynamics, when a system receives heat Q and does work W, the increase in internal energy ΔU equals:

  • A. Q − WCorrect
  • B. Q + W
  • C. W − Q
  • D. QW

Explanation

First law: ΔU=Q-W.

Physics 2025 Objective — Question 21

A stretched string of length 1.0 m has wave speed 200 ms⁻¹. The fundamental frequency is:

  • A. 50 Hz
  • B. 100 HzCorrect
  • C. 200 Hz
  • D. 400 Hz

Explanation

f₀=v/2L=200/2=100 Hz.

Physics 2025 Objective — Question 23

An object 10 cm tall is placed 30 cm from a concave mirror of focal length 20 cm. The image produced is:

  • A. 20 cm behind the mirror and upright
  • B. 60 cm in front of the mirror and invertedCorrect
  • C. 60 cm behind the mirror
  • D. 10 cm in front of the mirror

Explanation

1/f=1/u+1/v → v=60 cm; real, inverted, 60 cm in front.

Physics 2025 Objective — Question 24

Two point charges +5μC and −3μC are 0.2 m apart. k=9×10⁹ Nm²C⁻². The force between them is approximately:

  • A. 0.375 N
  • B. 1.35 N
  • C. 3.38 NCorrect
  • D. 7.5 N

Explanation

F=kq₁q₂/r²=9×10⁹×15×10⁻¹²/0.04=3.375 N≈3.38 N.

Physics 2025 Objective — Question 25

Which statement about electric field lines is correct?

  • A. they intersect where fields are equal
  • B. they indicate direction of motion of a negative test charge
  • C. they originate from positive charges and end on negative chargesCorrect
  • D. they are circles around a source charge

Explanation

Field lines go from + to − charges; direction shows force on positive test charge.

Physics 2025 Objective — Question 27

A battery of emf 12 V and internal resistance 2 Ω is connected to a 10 Ω resistor. The terminal voltage is:

  • A. 2 V
  • B. 10 VCorrect
  • C. 11 V
  • D. 14 V

Explanation

I=12/12=1 A; V_t=E-Ir=12-2=10 V.

Physics 2025 Objective — Question 28

The induced emf in a coil increases when:

  • A. the coil's resistance increases
  • B. a stronger magnet is usedCorrect
  • C. the magnet is moved more slowly
  • D. the coil has fewer turns

Explanation

Faraday: emf ∝ dΦ/dt; stronger magnet increases flux change, increasing emf.

Physics 2025 Objective — Question 30

A transformer has 500 primary turns and 100 secondary turns. If 240 V AC is applied, the secondary voltage is:

  • A. 48 VCorrect
  • B. 80 V
  • C. 1200 V
  • D. 120 V

Explanation

V_s=V_p×(N_s/N_p)=240×(100/500)=48 V.

Physics 2025 Objective — Question 31

The most suitable material for the core of a transformer is:

  • A. brass
  • B. wood
  • C. copper
  • D. soft ironCorrect

Explanation

Soft iron has high permeability and low hysteresis loss.

Physics 2025 Objective — Question 32

The energy of a photon with wavelength 50 cm is about: (h=6.63×10⁻³⁴ Js, c=3×10⁸ ms⁻¹)

  • A. 3.98×10⁻²⁵ JCorrect
  • B. 2.49×10⁻¹⁹ J
  • C. 6.63×10⁻²⁶ J
  • D. 1.99×10⁻²⁵ J

Explanation

E=hc/λ=(6.63×10⁻³⁴×3×10⁸)/0.5=3.978×10⁻²⁵ J≈3.98×10⁻²⁵ J.

Physics 2025 Objective — Question 33

Half-life of a radioactive isotope is 3 hours. Fraction remaining after 9 hours:

  • A. 1/8Correct
  • B. 1/9
  • C. 1/27
  • D. 1/32

Explanation

n=9/3=3 half-lives; fraction=(1/2)³=1/8.

Physics 2025 Objective — Question 34

The work function of a metal is 2.0 eV. The threshold frequency for photoemission is:

  • A. 2.4×10¹⁴ Hz
  • B. 4.8×10¹⁴ HzCorrect
  • C. 3.2×10¹⁵ Hz
  • D. 6.6×10¹³ Hz

Explanation

f₀=W/h=(2×1.6×10⁻¹⁹)/(6.63×10⁻³⁴)≈4.8×10¹⁴ Hz.

Physics 2025 Objective — Question 35

Which statement about the photoelectric effect is correct?

  • A. electrons emitted only when intensity exceeds a threshold
  • B. emission begins immediately once frequency exceeds thresholdCorrect
  • C. KE of emitted electrons is independent of frequency
  • D. number of electrons decreases as intensity increases

Explanation

Emission is instantaneous once frequency exceeds threshold; no time delay.

Physics 2025 Objective — Question 36

A current of 2 A flows through a wire 0.4 m long in a field of 0.5 T (perpendicular). The force on the wire is:

  • A. 0.2 N
  • B. 0.8 N
  • C. 0.4 NCorrect
  • D. 1.0 N

Explanation

F=BIL sin90°=0.5×2×0.4=0.4 N.

Physics 2025 Objective — Question 37

The electrostatic potential energy of two point charges q₁, q₂ separated by r is:

  • A. U=kq₁q₂
  • B. U=kq₁q₂/r²
  • C. U=q₁q₂/r
  • D. U=kq₁q₂/rCorrect

Explanation

U=kq₁q₂/r (Coulomb potential energy formula).

Physics 2025 Objective — Question 38

An ideal gas undergoes isothermal expansion. Which quantity remains constant?

  • A. internal energyCorrect
  • B. pressure
  • C. volume
  • D. temperature

Explanation

For ideal gas, internal energy depends only on T; isothermal → T constant → U constant.

Physics 2025 Objective — Question 39

Work function is 3 eV. Light of frequency 8×10¹⁴ Hz strikes the metal. Max KE of photoelectrons:

  • A. 0.2 eV
  • B. 0.5 eV
  • C. 0.3 eVCorrect
  • D. 0.4 eV

Explanation

E_photon=hf≈3.315 eV; KE_max=3.315-3=0.315 eV≈0.3 eV.

Physics 2025 Objective — Question 40

Kirchhoff's first law (junction rule) states that:

  • A. sum of currents entering = sum leaving a junctionCorrect
  • B. sum of all PDs in a loop is zero
  • C. total resistance in series = sum of individual
  • D. voltage across conductor ∝ current

Explanation

KCL is based on conservation of charge: currents in = currents out at a junction.

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