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Post-UTME Chemistry 2011 Objective Past Questions

All 10 questions from the Post-UTME Screening (Post-UTME) Chemistry 2011 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Chemistry 2011 Objective — Question 1

One mole of propane is mixed with five moles of oxygen. The mixture is ignited, what is the volume of the products at s.t.p?

  • A. 112.0dm³
  • B. 67.2dm³Correct
  • C. 56.0dm³
  • D. 44dm³

Explanation

C3H8+5O2→3CO2+4H2O. 1 mole propane gives 3 moles CO2; volume=3×22.4=67.2dm³.

Chemistry 2011 Objective — Question 2

Which of the following acts both as a reducing and an oxidizing agent?

  • A. H2
  • B. SO2Correct
  • C. H2S

Explanation

SO2 can act as either a reducing or oxidizing agent depending on the reaction partner.

Chemistry 2011 Objective — Question 3

What is the partial pressure of hydrogen gas collected over water at a standard atmospheric pressure and 25°C, if the saturation vapour pressure of water is 23mm Hg at that temperature?

  • A. 737mmHgCorrect
  • B. 763mmHg
  • C. 777mmHg
  • D. 783mmHg

Explanation

Partial pressure of H2 = total pressure - vapour pressure of water = 760-23=737mmHg.

Chemistry 2011 Objective — Question 4

A hydrated salt of formula MSO4·xH2O contains 45.3% by mass of water of crystallization. Calculate the value of x. [M=56, S=32, O=16, H=1]

  • A. 3
  • B. 5
  • C. 7Correct
  • D. 10

Explanation

Molar mass of hydrate=152+18x. Setting 18x/(152+18x)=0.453 and solving gives x≈7.

Chemistry 2011 Objective — Question 5

The pOH of a solution of 0.25 mol dm⁻³ of hydrochloric acid is

  • A. 12.40
  • B. 13.40Correct
  • C. 14.40
  • D. 14.60

Explanation

pH=-log(0.25)≈0.602; pOH=14-0.602≈13.40.

Chemistry 2011 Objective — Question 6

½Zn²⁺(aq)+e→½Zn(s). In the reaction above, calculate the quantity of electricity required to discharge 0.5 mol of zinc. [F=96,500 C mol⁻¹]

  • A. 0.965×10⁴C
  • B. 4.820×10⁴C
  • C. 9.650×10⁴CCorrect
  • D. 48.200×10⁴C

Explanation

Quantity of electricity=0.5×96500×2=9.650×10⁴C.

Chemistry 2011 Objective — Question 7

Deliquescent substances are used for

  • A. cooling
  • B. wetting
  • C. dryingCorrect

Explanation

Deliquescent substances absorb moisture from the air and are used as drying agents (desiccants).

Chemistry 2011 Objective — Question 8

Which of the following best explains the increase in the rate of a chemical reaction as the temperature rises?

  • A. The bonds in the reacting molecules are more readily broken
  • B. The molecular collisions become more violent
  • C. A lower proportion of the molecules has the necessary minimum energy to react
  • D. The collision frequency of the molecules increasesCorrect

Explanation

Per the source key, increased collision frequency is marked as the answer; note most textbooks primarily attribute the rate increase to a greater proportion of molecules exceeding the activation energy, so this is worth double-checking against your syllabus.

Chemistry 2011 Objective — Question 9

NH2-CH-C(=O)-OH: the two functional groups in the above compound are

  • A. alcohol and amine
  • B. acid and amineCorrect
  • C. aldehyde and acid
  • D. ketone and amine

Explanation

This is an amino acid structure, containing both a carboxylic acid group and an amine group.

Chemistry 2011 Objective — Question 10

CH3C(=O)OCH2CH3 (an ester) and CH3CH2CH2C(=O)OH (a carboxylic acid) are

  • A. isomersCorrect
  • B. esters
  • C. carboxylic acids
  • D. polymers

Explanation

Both compounds share the molecular formula C4H8O2, making them (functional group) isomers.

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