Post-UTME Chemistry 2011 Objective — Question 6
Question 6 of 10 from the Post-UTME Screening (Post-UTME) Chemistry 2011 Objective paper, with the correct answer and a full explanation.
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½Zn²⁺(aq)+e→½Zn(s). In the reaction above, calculate the quantity of electricity required to discharge 0.5 mol of zinc. [F=96,500 C mol⁻¹]
- A. 0.965×10⁴C
- B. 4.820×10⁴C
- C. 9.650×10⁴CCorrect
- D. 48.200×10⁴C
Explanation
Quantity of electricity=0.5×96500×2=9.650×10⁴C.
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